Let’s find the products using the formula $(a + b)(a – b) = a^2 – b^2$.
Hint: $99 times 101 = (100 – 1) times (100 + 1) = 100^2 – 1^2 = 10000 – 1 = 9999$
a) $19 times 21$
b) $49 times 51$
c) $78 times 82$
d) $102 times 98$
1 Marks
Let’s find the products using the formula $(a + b)(a – b) = a^2 – b^2$.
Hint: $99 times 101 = (100 – 1) times (100 + 1) = 100^2 – 1^2 = 10000 – 1 = 9999$
a) $19 times 21$
b) $49 times 51$
c) $78 times 82$
d) $102 times 98$
Select sub-parts from the list to begin.
Study Solution
Solution Locked
You need to purchase the Subject Bundle or Mega Bundle to view this solution.
